3n-3(2n-8)=-6(n-2)

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Solution for 3n-3(2n-8)=-6(n-2) equation: 



3n-3(2n-8)=-6(n-2)

We move all terms to the left:

3n-3(2n-8)-(-6(n-2))=0

We multiply parentheses

3n-6n-(-6(n-2))+24=0



We calculate terms in parentheses: -(-6(n-2)), so:

-6(n-2)

We multiply parentheses

-6n+12

Back to the equation:

-(-6n+12)



We add all the numbers together, and all the variables

-3n-(-6n+12)+24=0

We get rid of parentheses

-3n+6n-12+24=0

We add all the numbers together, and all the variables

3n+12=0

We move all terms containing n to the left, all other terms to the right

3n=-12

n=-12/3

n=-4

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