3n-4(n-2)=5(n-2)

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Solution for 3n-4(n-2)=5(n-2) equation:



3n-4(n-2)=5(n-2)
We move all terms to the left:
3n-4(n-2)-(5(n-2))=0
We multiply parentheses
3n-4n-(5(n-2))+8=0
We calculate terms in parentheses: -(5(n-2)), so:
5(n-2)
We multiply parentheses
5n-10
Back to the equation:
-(5n-10)
We add all the numbers together, and all the variables
-1n-(5n-10)+8=0
We get rid of parentheses
-1n-5n+10+8=0
We add all the numbers together, and all the variables
-6n+18=0
We move all terms containing n to the left, all other terms to the right
-6n=-18
n=-18/-6
n=+3

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