3n-4n(n+1)=19

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Solution for 3n-4n(n+1)=19 equation: 



3n-4n(n+1)=19

We move all terms to the left:

3n-4n(n+1)-(19)=0

We multiply parentheses

-4n^2+3n-4n-19=0

We add all the numbers together, and all the variables

-4n^2-1n-19=0

a = -4; b = -1; c = -19;
Δ = b2-4ac
Δ = -12-4·(-4)·(-19)
Δ = -303
Delta is less than zero, so there is no solution for the equation

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