3n-4n(n-2)=15

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Solution for 3n-4n(n-2)=15 equation: 



3n-4n(n-2)=15

We move all terms to the left:

3n-4n(n-2)-(15)=0

We multiply parentheses

-4n^2+3n+8n-15=0

We add all the numbers together, and all the variables

-4n^2+11n-15=0

a = -4; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·(-4)·(-15)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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