3n-6(2n+2)=28-4n

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Solution for 3n-6(2n+2)=28-4n equation: 



3n-6(2n+2)=28-4n

We move all terms to the left:

3n-6(2n+2)-(28-4n)=0

We add all the numbers together, and all the variables

3n-6(2n+2)-(-4n+28)=0

We multiply parentheses

3n-12n-(-4n+28)-12=0

We get rid of parentheses

3n-12n+4n-28-12=0

We add all the numbers together, and all the variables

-5n-40=0

We move all terms containing n to the left, all other terms to the right

-5n=40

n=40/-5

n=-8

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