3n/4x12-1/3x12=2n-1/6x12

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Solution for 3n/4x12-1/3x12=2n-1/6x12 equation:


x in (-oo:+oo)

((3*n)/4)*x^12-((1/3)*x^12) = 2*n-((1/6)*x^12) // - 2*n-((1/6)*x^12)

((3*n)/4)*x^12-(2*n)-((1/3)*x^12)+(1/6)*x^12 = 0

((3*n)/4)*x^12-2*n+(-1/3)*x^12+(1/6)*x^12 = 0

3/4*n*x^12-2*n-1/6*x^12 = 0

t_1 = x^12

3/4*n*t_1^1-2*n-1/6*t_1^1 = 0

-2*n-1/6*t_1 = 0 // + -2*n

-1/6*t_1 = -(-2*n) // : -1/6

t_1 = (-(-2*n))/(-1/6)

t_1 = -12*n

t_1 = -12*n

x^12-(-12*n) = 0

12*n+x^12 = 0

1*x^12 = -(12*n) // : 1

x^12 = -12*n

x^12 = -12*n // ^ 1/12

abs(x) = (-12)^(1/12)*n^(1/12)

x = (-12)^(1/12)*n^(1/12) or x = -((-12)^(1/12)*n^(1/12))

x in { (-12)^(1/12)*n^(1/12), -((-12)^(1/12)*n^(1/12)) }

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