3n/5n+9/10+n/5=-23/10

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Solution for 3n/5n+9/10+n/5=-23/10 equation: 


n in (-oo:+oo)

((3*n)/5)*n+n/5+9/10 = -23/10 // + -23/10

((3*n)/5)*n+n/5+9/10-(-23/10) = 0

((3*n)/5)*n+n/5+9/10+23/10 = 0

3/5*n^2+1/5*n+16/5 = 0

DELTA = (1/5)^2-(3/5*16/5*4)

DELTA = -191/25

DELTA < 0

n belongs to the empty set

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