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3n^2+7n-26=0
a = 3; b = 7; c = -26;
Δ = b2-4ac
Δ = 72-4·3·(-26)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-19}{2*3}=\frac{-26}{6} =-4+1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+19}{2*3}=\frac{12}{6} =2 $
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