3n2+803n-45456=0

Solution for 3n2+803n-45456=0 equation:

3n^2+803n-45456=0

a = 3; b = 803; c = -45456;
Δ = b2-4ac
Δ = 8032-4·3·(-45456)
Δ = 1190281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1190281}=1091$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(803)-1091}{2*3}=\frac{-1894}{6}
=-315+2/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(803)+1091}{2*3}=\frac{288}{6}
=48
$