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3n^2-6n-144=0
a = 3; b = -6; c = -144;
Δ = b2-4ac
Δ = -62-4·3·(-144)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-42}{2*3}=\frac{-36}{6} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+42}{2*3}=\frac{48}{6} =8 $
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