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3n^2-n-184=0
We add all the numbers together, and all the variables
3n^2-1n-184=0
a = 3; b = -1; c = -184;
Δ = b2-4ac
Δ = -12-4·3·(-184)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-47}{2*3}=\frac{-46}{6} =-7+2/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+47}{2*3}=\frac{48}{6} =8 $
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