3n=3(1-n)=n-6

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Solution for 3n=3(1-n)=n-6 equation: 



3n=3(1-n)=n-6

We move all terms to the left:

3n-(3(1-n))=0

We add all the numbers together, and all the variables

3n-(3(-1n+1))=0



We calculate terms in parentheses: -(3(-1n+1)), so:

3(-1n+1)

We multiply parentheses

-3n+3

Back to the equation:

-(-3n+3)



We get rid of parentheses

3n+3n-3=0

We add all the numbers together, and all the variables

6n-3=0

We move all terms containing n to the left, all other terms to the right

6n=3

n=3/6

n=1/2

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