3p(2p-7)=0

Solution for 3p(2p-7)=0 equation:

3p(2p-7)=0

We multiply parentheses

6p^2-21p=0

a = 6; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·6·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*6}=\frac{0}{12}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*6}=\frac{42}{12}
=3+1/2
$