3p(p+1)-2(p-5)=p(p-5)

Solution for 3p(p+1)-2(p-5)=p(p-5) equation:

3p(p+1)-2(p-5)=p(p-5)

We move all terms to the left:

3p(p+1)-2(p-5)-(p(p-5))=0

We multiply parentheses

3p^2+3p-2p-(p(p-5))+10=0


We calculate terms in parentheses: -(p(p-5)), so:

p(p-5)

We multiply parentheses

p^2-5p

Back to the equation:

-(p^2-5p)


We add all the numbers together, and all the variables

3p^2+p-(p^2-5p)+10=0

We get rid of parentheses

3p^2-p^2+p+5p+10=0

We add all the numbers together, and all the variables

2p^2+6p+10=0

a = 2; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·2·10
Δ = -44
Delta is less than zero, so there is no solution for the equation