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3p*p+4p=20
We move all terms to the left:
3p*p+4p-(20)=0
We add all the numbers together, and all the variables
4p+3p*p-20=0
Wy multiply elements
3p^2+4p-20=0
a = 3; b = 4; c = -20;
Δ = b2-4ac
Δ = 42-4·3·(-20)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16}{2*3}=\frac{-20}{6} =-3+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16}{2*3}=\frac{12}{6} =2 $
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