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3p+2=12-(2-p)
We move all terms to the left:
3p+2-(12-(2-p))=0
We add all the numbers together, and all the variables
3p-(12-(-1p+2))+2=0
We calculate terms in parentheses: -(12-(-1p+2)), so:We get rid of parentheses
12-(-1p+2)
determiningTheFunctionDomain -(-1p+2)+12
We get rid of parentheses
1p-2+12
We add all the numbers together, and all the variables
p+10
Back to the equation:
-(p+10)
3p-p-10+2=0
We add all the numbers together, and all the variables
2p-8=0
We move all terms containing p to the left, all other terms to the right
2p=8
p=8/2
p=4
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