3p+2=4(p-4)+5(p+3)

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Solution for 3p+2=4(p-4)+5(p+3) equation: 



3p+2=4(p-4)+5(p+3)

We move all terms to the left:

3p+2-(4(p-4)+5(p+3))=0



We calculate terms in parentheses: -(4(p-4)+5(p+3)), so:

4(p-4)+5(p+3)

We multiply parentheses

4p+5p-16+15

We add all the numbers together, and all the variables

9p-1

Back to the equation:

-(9p-1)



We get rid of parentheses

3p-9p+1+2=0

We add all the numbers together, and all the variables

-6p+3=0

We move all terms containing p to the left, all other terms to the right

-6p=-3

p=-3/-6

p=1/2

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