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3p+4p(p+11)=79
We move all terms to the left:
3p+4p(p+11)-(79)=0
We multiply parentheses
4p^2+3p+44p-79=0
We add all the numbers together, and all the variables
4p^2+47p-79=0
a = 4; b = 47; c = -79;
Δ = b2-4ac
Δ = 472-4·4·(-79)
Δ = 3473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{3473}}{2*4}=\frac{-47-\sqrt{3473}}{8} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{3473}}{2*4}=\frac{-47+\sqrt{3473}}{8} $
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