3p-8(p+2)=6-(p+2)

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Solution for 3p-8(p+2)=6-(p+2) equation: 



3p-8(p+2)=6-(p+2)

We move all terms to the left:

3p-8(p+2)-(6-(p+2))=0

We multiply parentheses

3p-8p-(6-(p+2))-16=0



We calculate terms in parentheses: -(6-(p+2)), so:

6-(p+2)

determiningTheFunctionDomain
-(p+2)+6

We get rid of parentheses

-p-2+6

We add all the numbers together, and all the variables

-1p+4

Back to the equation:

-(-1p+4)



We add all the numbers together, and all the variables

-5p-(-1p+4)-16=0

We get rid of parentheses

-5p+1p-4-16=0

We add all the numbers together, and all the variables

-4p-20=0

We move all terms containing p to the left, all other terms to the right

-4p=20

p=20/-4

p=-5

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