3p2-18p=81=0

Solution for 3p2-18p=81=0 equation:

3p^2-18p=81=0

We move all terms to the left:

3p^2-18p-(81)=0

a = 3; b = -18; c = -81;
Δ = b2-4ac
Δ = -182-4·3·(-81)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-36}{2*3}=\frac{-18}{6}
=-3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+36}{2*3}=\frac{54}{6}
=9
$