3p2-400=275

Solution for 3p2-400=275 equation:

3p^2-400=275

We move all terms to the left:

3p^2-400-(275)=0

We add all the numbers together, and all the variables

3p^2-675=0

a = 3; b = 0; c = -675;
Δ = b2-4ac
Δ = 02-4·3·(-675)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*3}=\frac{-90}{6}
=-15
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*3}=\frac{90}{6}
=15
$