3q(3-2)=2(2q+5)

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Solution for 3q(3-2)=2(2q+5) equation: 



3q(3-2)=2(2q+5)

We move all terms to the left:

3q(3-2)-(2(2q+5))=0

We add all the numbers together, and all the variables

3q1-(2(2q+5))=0

We add all the numbers together, and all the variables

3q-(2(2q+5))=0



We calculate terms in parentheses: -(2(2q+5)), so:

2(2q+5)

We multiply parentheses

4q+10

Back to the equation:

-(4q+10)



We get rid of parentheses

3q-4q-10=0

We add all the numbers together, and all the variables

-1q-10=0

We move all terms containing q to the left, all other terms to the right

-q=10

q=10/-1

q=-10

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