3q*2q=6q

Solution for 3q*2q=6q equation:

3q*2q=6q

We move all terms to the left:

3q*2q-(6q)=0

We add all the numbers together, and all the variables

-6q+3q*2q=0

Wy multiply elements

6q^2-6q=0

a = 6; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·6·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*6}=\frac{0}{12}
=0
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*6}=\frac{12}{12}
=1
$