3q+12=3(q+4)

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Solution for 3q+12=3(q+4) equation:


Simplifying
3q + 12 = 3(q + 4)

Reorder the terms:
12 + 3q = 3(q + 4)

Reorder the terms:
12 + 3q = 3(4 + q)
12 + 3q = (4 * 3 + q * 3)
12 + 3q = (12 + 3q)

Add '-12' to each side of the equation.
12 + -12 + 3q = 12 + -12 + 3q

Combine like terms: 12 + -12 = 0
0 + 3q = 12 + -12 + 3q
3q = 12 + -12 + 3q

Combine like terms: 12 + -12 = 0
3q = 0 + 3q
3q = 3q

Add '-3q' to each side of the equation.
3q + -3q = 3q + -3q

Combine like terms: 3q + -3q = 0
0 = 3q + -3q

Combine like terms: 3q + -3q = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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