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3q+5(q+1)=3(q+5)
We move all terms to the left:
3q+5(q+1)-(3(q+5))=0
We multiply parentheses
3q+5q-(3(q+5))+5=0
We calculate terms in parentheses: -(3(q+5)), so:We add all the numbers together, and all the variables
3(q+5)
We multiply parentheses
3q+15
Back to the equation:
-(3q+15)
8q-(3q+15)+5=0
We get rid of parentheses
8q-3q-15+5=0
We add all the numbers together, and all the variables
5q-10=0
We move all terms containing q to the left, all other terms to the right
5q=10
q=10/5
q=2
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