3q-(8q+13)=7-(8q-2)

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Solution for 3q-(8q+13)=7-(8q-2) equation: 



3q-(8q+13)=7-(8q-2)

We move all terms to the left:

3q-(8q+13)-(7-(8q-2))=0

We get rid of parentheses

3q-8q-(7-(8q-2))-13=0



We calculate terms in parentheses: -(7-(8q-2)), so:

7-(8q-2)

determiningTheFunctionDomain
-(8q-2)+7

We get rid of parentheses

-8q+2+7

We add all the numbers together, and all the variables

-8q+9

Back to the equation:

-(-8q+9)



We add all the numbers together, and all the variables

-5q-(-8q+9)-13=0

We get rid of parentheses

-5q+8q-9-13=0

We add all the numbers together, and all the variables

3q-22=0

We move all terms containing q to the left, all other terms to the right

3q=22

q=22/3

q=7+1/3

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