3q-(q+2)=2(q-1)

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Solution for 3q-(q+2)=2(q-1) equation:


Simplifying
3q + -1(q + 2) = 2(q + -1)

Reorder the terms:
3q + -1(2 + q) = 2(q + -1)
3q + (2 * -1 + q * -1) = 2(q + -1)
3q + (-2 + -1q) = 2(q + -1)

Reorder the terms:
-2 + 3q + -1q = 2(q + -1)

Combine like terms: 3q + -1q = 2q
-2 + 2q = 2(q + -1)

Reorder the terms:
-2 + 2q = 2(-1 + q)
-2 + 2q = (-1 * 2 + q * 2)
-2 + 2q = (-2 + 2q)

Add '2' to each side of the equation.
-2 + 2 + 2q = -2 + 2 + 2q

Combine like terms: -2 + 2 = 0
0 + 2q = -2 + 2 + 2q
2q = -2 + 2 + 2q

Combine like terms: -2 + 2 = 0
2q = 0 + 2q
2q = 2q

Add '-2q' to each side of the equation.
2q + -2q = 2q + -2q

Combine like terms: 2q + -2q = 0
0 = 2q + -2q

Combine like terms: 2q + -2q = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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