3q-16q=7+2(-8q-30

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Solution for 3q-16q=7+2(-8q-30 equation: 



3q-16q=7+2(-8q-30

We move all terms to the left:

3q-16q-(7+2(-8q-30)=0

We add all the numbers together, and all the variables

-13q-(7+2(-8q-30)=0



We calculate terms in parentheses: -(7+2(-8q-30), so:

7+2(-8q-30

determiningTheFunctionDomain
2(-8q-30+7

Back to the equation:

-(2(-8q-30+7)



We add all the numbers together, and all the variables

-13q-(2(-8q-23)=0



We calculate terms in parentheses: -(2(-8q-23), so:

2(-8q-23





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2(-8q-23





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2(-8q-23





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2(-8q-23





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2(-8q-23





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2(-8q-23





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2(-8q-23





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