3q-16q=7+2(18q-3)

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Solution for 3q-16q=7+2(18q-3) equation: 



3q-16q=7+2(18q-3)

We move all terms to the left:

3q-16q-(7+2(18q-3))=0

We add all the numbers together, and all the variables

-13q-(7+2(18q-3))=0



We calculate terms in parentheses: -(7+2(18q-3)), so:

7+2(18q-3)

determiningTheFunctionDomain
2(18q-3)+7

We multiply parentheses

36q-6+7

We add all the numbers together, and all the variables

36q+1

Back to the equation:

-(36q+1)



We get rid of parentheses

-13q-36q-1=0

We add all the numbers together, and all the variables

-49q-1=0

We move all terms containing q to the left, all other terms to the right

-49q=1

q=1/-49

q=-1/49

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