3q-16q=7+3(-8q-3)

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Solution for 3q-16q=7+3(-8q-3) equation: 



3q-16q=7+3(-8q-3)

We move all terms to the left:

3q-16q-(7+3(-8q-3))=0

We add all the numbers together, and all the variables

-13q-(7+3(-8q-3))=0



We calculate terms in parentheses: -(7+3(-8q-3)), so:

7+3(-8q-3)

determiningTheFunctionDomain
3(-8q-3)+7

We multiply parentheses

-24q-9+7

We add all the numbers together, and all the variables

-24q-2

Back to the equation:

-(-24q-2)



We get rid of parentheses

-13q+24q+2=0

We add all the numbers together, and all the variables

11q+2=0

We move all terms containing q to the left, all other terms to the right

11q=-2

q=-2/11

q=-2/11

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