3q-20=19+6q+12

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Solution for 3q-20=19+6q+12 equation: 



3q-20=19+6q+12

We move all terms to the left:

3q-20-(19+6q+12)=0

We add all the numbers together, and all the variables

3q-(6q+31)-20=0

We get rid of parentheses

3q-6q-31-20=0

We add all the numbers together, and all the variables

-3q-51=0

We move all terms containing q to the left, all other terms to the right

-3q=51

q=51/-3

q=-17

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