3q-25/q=0

Solution for 3q-25/q=0 equation:

3q-25/q=0


Domain of the equation: q!=0

q∈R


We multiply all the terms by the denominator


3q*q-25=0

Wy multiply elements

3q^2-25=0

a = 3; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·3·(-25)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*3}=\frac{0-10\sqrt{3}}{6}
=-\frac{10\sqrt{3}}{6}
=-\frac{5\sqrt{3}}{3}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*3}=\frac{0+10\sqrt{3}}{6}
=\frac{10\sqrt{3}}{6}
=\frac{5\sqrt{3}}{3}
$