3q-8=6/q

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Solution for 3q-8=6/q equation: 


D( q )

q = 0

q = 0

q = 0

q in (-oo:0) U (0:+oo)

3*q-8 = 6/q // - 6/q

3*q-(6/q)-8 = 0

3*q-6*q^-1-8 = 0

3*q^1-6*q^-1-8*q^0 = 0

(3*q^2-8*q^1-6*q^0)/(q^1) = 0 // * q^2

q^1*(3*q^2-8*q^1-6*q^0) = 0

q^1

3*q^2-8*q-6 = 0

3*q^2-8*q-6 = 0

DELTA = (-8)^2-(-6*3*4)

DELTA = 136

DELTA > 0

q = (136^(1/2)+8)/(2*3) or q = (8-136^(1/2))/(2*3)

q = (2*34^(1/2)+8)/6 or q = (8-2*34^(1/2))/6

q in { (8-2*34^(1/2))/6, (2*34^(1/2)+8)/6} 

q in { (8-2*34^(1/2))/6, (2*34^(1/2)+8)/6 }

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