3q=9q/10+42

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Solution for 3q=9q/10+42 equation:



3q=9q/10+42
We move all terms to the left:
3q-(9q/10+42)=0
We get rid of parentheses
3q-9q/10-42=0
We multiply all the terms by the denominator
3q*10-9q-42*10=0
We add all the numbers together, and all the variables
-9q+3q*10-420=0
Wy multiply elements
-9q+30q-420=0
We add all the numbers together, and all the variables
21q-420=0
We move all terms containing q to the left, all other terms to the right
21q=420
q=420/21
q=20

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