3r+-2(r-2)+1=2(5r-3)

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Solution for 3r+-2(r-2)+1=2(5r-3) equation: 



3r+-2(r-2)+1=2(5r-3)

We move all terms to the left:

3r+-2(r-2)+1-(2(5r-3))=0

We add all the numbers together, and all the variables

3r-2(r-2)-(2(5r-3))=0

We multiply parentheses

3r-2r-(2(5r-3))+4=0



We calculate terms in parentheses: -(2(5r-3)), so:

2(5r-3)

We multiply parentheses

10r-6

Back to the equation:

-(10r-6)



We add all the numbers together, and all the variables

r-(10r-6)+4=0

We get rid of parentheses

r-10r+6+4=0

We add all the numbers together, and all the variables

-9r+10=0

We move all terms containing r to the left, all other terms to the right

-9r=-10

r=-10/-9

r=1+1/9

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