3r+-8=2(r-4)+r

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Solution for 3r+-8=2(r-4)+r equation:


Simplifying
3r + -8 = 2(r + -4) + r

Reorder the terms:
-8 + 3r = 2(r + -4) + r

Reorder the terms:
-8 + 3r = 2(-4 + r) + r
-8 + 3r = (-4 * 2 + r * 2) + r
-8 + 3r = (-8 + 2r) + r

Combine like terms: 2r + r = 3r
-8 + 3r = -8 + 3r

Add '8' to each side of the equation.
-8 + 8 + 3r = -8 + 8 + 3r

Combine like terms: -8 + 8 = 0
0 + 3r = -8 + 8 + 3r
3r = -8 + 8 + 3r

Combine like terms: -8 + 8 = 0
3r = 0 + 3r
3r = 3r

Add '-3r' to each side of the equation.
3r + -3r = 3r + -3r

Combine like terms: 3r + -3r = 0
0 = 3r + -3r

Combine like terms: 3r + -3r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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