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3r+11=2(r+2)+1
We move all terms to the left:
3r+11-(2(r+2)+1)=0
We calculate terms in parentheses: -(2(r+2)+1), so:We get rid of parentheses
2(r+2)+1
We multiply parentheses
2r+4+1
We add all the numbers together, and all the variables
2r+5
Back to the equation:
-(2r+5)
3r-2r-5+11=0
We add all the numbers together, and all the variables
r+6=0
We move all terms containing r to the left, all other terms to the right
r=-6
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