3r+3=-3+6(1+7r)

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Solution for 3r+3=-3+6(1+7r) equation:



3r+3=-3+6(1+7r)
We move all terms to the left:
3r+3-(-3+6(1+7r))=0
We add all the numbers together, and all the variables
3r-(-3+6(7r+1))+3=0
We calculate terms in parentheses: -(-3+6(7r+1)), so:
-3+6(7r+1)
determiningTheFunctionDomain 6(7r+1)-3
We multiply parentheses
42r+6-3
We add all the numbers together, and all the variables
42r+3
Back to the equation:
-(42r+3)
We get rid of parentheses
3r-42r-3+3=0
We add all the numbers together, and all the variables
-39r=0
r=0/-39
r=0

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