3r+4=30/r

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Solution for 3r+4=30/r equation:



3r+4=30/r
We move all terms to the left:
3r+4-(30/r)=0
Domain of the equation: r)!=0
r!=0/1
r!=0
r∈R
We add all the numbers together, and all the variables
3r-(+30/r)+4=0
We get rid of parentheses
3r-30/r+4=0
We multiply all the terms by the denominator
3r*r+4*r-30=0
We add all the numbers together, and all the variables
4r+3r*r-30=0
Wy multiply elements
3r^2+4r-30=0
a = 3; b = 4; c = -30;
Δ = b2-4ac
Δ = 42-4·3·(-30)
Δ = 376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{376}=\sqrt{4*94}=\sqrt{4}*\sqrt{94}=2\sqrt{94}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{94}}{2*3}=\frac{-4-2\sqrt{94}}{6} $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{94}}{2*3}=\frac{-4+2\sqrt{94}}{6} $

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