3r-13=7(r+2)-4(r-7)

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Solution for 3r-13=7(r+2)-4(r-7) equation: 



3r-13=7(r+2)-4(r-7)

We move all terms to the left:

3r-13-(7(r+2)-4(r-7))=0



We calculate terms in parentheses: -(7(r+2)-4(r-7)), so:

7(r+2)-4(r-7)

We multiply parentheses

7r-4r+14+28

We add all the numbers together, and all the variables

3r+42

Back to the equation:

-(3r+42)



We get rid of parentheses

3r-3r-42-13=0

We add all the numbers together, and all the variables

-55!=0

There is no solution for this equation

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