3r-3+8r+6=5(3r-7)-2(r-4)

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Solution for 3r-3+8r+6=5(3r-7)-2(r-4) equation: 



3r-3+8r+6=5(3r-7)-2(r-4)

We move all terms to the left:

3r-3+8r+6-(5(3r-7)-2(r-4))=0

We add all the numbers together, and all the variables

11r-(5(3r-7)-2(r-4))+3=0



We calculate terms in parentheses: -(5(3r-7)-2(r-4)), so:

5(3r-7)-2(r-4)

We multiply parentheses

15r-2r-35+8

We add all the numbers together, and all the variables

13r-27

Back to the equation:

-(13r-27)



We get rid of parentheses

11r-13r+27+3=0

We add all the numbers together, and all the variables

-2r+30=0

We move all terms containing r to the left, all other terms to the right

-2r=-30

r=-30/-2

r=+15

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