3r-5(r+1)=7r+58

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Solution for 3r-5(r+1)=7r+58 equation: 



3r-5(r+1)=7r+58

We move all terms to the left:

3r-5(r+1)-(7r+58)=0

We multiply parentheses

3r-5r-(7r+58)-5=0

We get rid of parentheses

3r-5r-7r-58-5=0

We add all the numbers together, and all the variables

-9r-63=0

We move all terms containing r to the left, all other terms to the right

-9r=63

r=63/-9

r=-7

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