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3r-5/r-7=6
We move all terms to the left:
3r-5/r-7-(6)=0
Domain of the equation: r!=0We add all the numbers together, and all the variables
r∈R
3r-5/r-13=0
We multiply all the terms by the denominator
3r*r-13*r-5=0
We add all the numbers together, and all the variables
-13r+3r*r-5=0
Wy multiply elements
3r^2-13r-5=0
a = 3; b = -13; c = -5;
Δ = b2-4ac
Δ = -132-4·3·(-5)
Δ = 229
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{229}}{2*3}=\frac{13-\sqrt{229}}{6} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{229}}{2*3}=\frac{13+\sqrt{229}}{6} $
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