3r-r2=5r-3r

Solution for 3r-r2=5r-3r equation:

3r-r2=5r-3r

We move all terms to the left:

3r-r2-(5r-3r)=0

We add all the numbers together, and all the variables

3r-r2-(+2r)=0

We add all the numbers together, and all the variables

-1r^2+3r-(+2r)=0

We get rid of parentheses

-1r^2+3r-2r=0

We add all the numbers together, and all the variables

-1r^2+r=0

a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2}
=1
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2}
=0
$