3s(s-12)=12s

Solution for 3s(s-12)=12s equation:

3s(s-12)=12s

We move all terms to the left:

3s(s-12)-(12s)=0

We add all the numbers together, and all the variables

-12s+3s(s-12)=0

We multiply parentheses

3s^2-12s-36s=0

We add all the numbers together, and all the variables

3s^2-48s=0

a = 3; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·3·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*3}=\frac{0}{6}
=0
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*3}=\frac{96}{6}
=16
$