3s(s-12)=12s

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Solution for 3s(s-12)=12s equation:



3s(s-12)=12s
We move all terms to the left:
3s(s-12)-(12s)=0
We add all the numbers together, and all the variables
-12s+3s(s-12)=0
We multiply parentheses
3s^2-12s-36s=0
We add all the numbers together, and all the variables
3s^2-48s=0
a = 3; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·3·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*3}=\frac{0}{6} =0 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*3}=\frac{96}{6} =16 $

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