3s+15=(1s+5)

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Solution for 3s+15=(1s+5) equation: 



3s+15=(1s+5)

We move all terms to the left:

3s+15-((1s+5))=0

We add all the numbers together, and all the variables

3s-((s+5))+15=0



We calculate terms in parentheses: -((s+5)), so:

(s+5)

We get rid of parentheses

s+5

Back to the equation:

-(s+5)



We get rid of parentheses

3s-s-5+15=0

We add all the numbers together, and all the variables

2s+10=0

We move all terms containing s to the left, all other terms to the right

2s=-10

s=-10/2

s=-5

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