3s-7=5+12(s+10)

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Solution for 3s-7=5+12(s+10) equation:



3s-7=5+12(s+10)
We move all terms to the left:
3s-7-(5+12(s+10))=0
We calculate terms in parentheses: -(5+12(s+10)), so:
5+12(s+10)
determiningTheFunctionDomain 12(s+10)+5
We multiply parentheses
12s+120+5
We add all the numbers together, and all the variables
12s+125
Back to the equation:
-(12s+125)
We get rid of parentheses
3s-12s-125-7=0
We add all the numbers together, and all the variables
-9s-132=0
We move all terms containing s to the left, all other terms to the right
-9s=132
s=132/-9
s=-14+2/3

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