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Simplifying 3sin(a) + 4cos(b) = 8 Multiply ins * a 3ains + 4cos(b) = 8 Multiply cos * b 3ains + 4bcos = 8 Solving 3ains + 4bcos = 8 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '-4bcos' to each side of the equation. 3ains + 4bcos + -4bcos = 8 + -4bcos Combine like terms: 4bcos + -4bcos = 0 3ains + 0 = 8 + -4bcos 3ains = 8 + -4bcos Divide each side by '3ins'. a = 2.666666667i-1n-1s-1 + -1.333333333bci-1n-1o Simplifying a = 2.666666667i-1n-1s-1 + -1.333333333bci-1n-1o Reorder the terms: a = -1.333333333bci-1n-1o + 2.666666667i-1n-1s-1
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