3t(t+15t)=0

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Solution for 3t(t+15t)=0 equation: 



3t(t+15t)=0

We add all the numbers together, and all the variables

3t(+16t)=0

We multiply parentheses

48t^2=0

a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{96}=0$

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