3t+1/5(6-t)=4

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Solution for 3t+1/5(6-t)=4 equation: 



3t+1/5(6-t)=4

We move all terms to the left:

3t+1/5(6-t)-(4)=0



Domain of the equation: 5(6-t)!=0

t∈R



We add all the numbers together, and all the variables

3t+1/5(-1t+6)-4=0

We multiply all the terms by the denominator


3t*5(-1t+6)-4*5(-1t+6)+1=0

Wy multiply elements

15t^2(--20t(-+1=0

We use the square of the difference formula

15t^2(+20t(-1=0

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